Verification Example - Composite Steel Beam Design Main Member (LRFD & ASD)

Tekla Tedds
Modified: 24 Jul 2025
2025
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Verification Example - Composite Steel Beam Design Main Member (LRFD & ASD)

Description

This verification example represents the analysis and design of a composite steel girder (main member) utilizing Tedds. This example is based on Design Example I.2 of the Companion to the AISC Steel Construction Manual Volume 1: Design Examples Version 15.1 (Pages I-15 through I-33). Comparisons and contrasts are tabularized and discussed regarding the results from Tedds and the AISC Design Example.

Problem statement

Select an appropriate ASTM A992 W-shaped girder and determine the required number of ¾” ⌀ steel headed stud anchors. The girder will not be shored during construction.

Tedds calculation

Composite beam design (AISC360) - Compared using version 1.0.19

Running the example in Tedds

The Tedds verification examples referenced in this document can be run in Tekla Tedds from the Engineering library index, in the Verification Examples\Composite beam design (AISC360) folder.

References

International Building Code (IBC) 2018

AISC Steel Construction Manual 15th ed.

Companion to the AISC Steel Construction Manual Volume 1: Design Examples Version 15.1

ANSI/AISC 360-16: Specification for Structural Steel Buildings

ACI 318-14: Building Code Requirements for Structural Concrete and Commentary

Example information

4-½” normal weight concrete on 3” x 18 ga. (Vulcraft 3VLI-36) composite deck (total slab thickness = 7-½”)

γconcrete = 145 lb/ft3

f’c = 4 ksi

ASTM A992

Fy = 50 ksi

Fu = 65 ksi

¾” ⌀ Steel stud anchors

Fu = 65 ksi

Stud height = 3” + 1-½” = 4-½” (AISC Section I3.2c)

Secondary beams are W21x50 composite beams spaced at 10’-0” o.c.

Short-term to long-term concrete elastic modulus = 3:1 (assumed)


Figure 1: Composite beam floor layout with girder to be analyzed and designed

 

Figure 2: Composite girder stud layout (AISC Example I.2)

 

Figure 3: Composite girder stud layout (Tedds output)

 
Applied Loads
Pre-Composite (Construction Stage)

Dead Load

75 lb/ft2 Composite slab (72-½ lb/ft2 (slab) and 2-½ lb/ft2 (deck))
50 lb/ft Self-weight of secondary steel beams
76 lb/ft Self-weight of girder
Construction Live Load 25 lb/ft2 Light duty (ASCE 37-14 Table 4-4)
Post-Composite
Dead 10 lb/ft2 Miscellaneous (HVAC, ceiling, floor covering, sprinklers, etc.)
Live 100 lb/ft2 Assembly occupancy (non-reducible) Live load is assumed to be 100% long-term, as no information is provided in the Design Example.
Serviceability Criteria
Pre-Composite (Construction Stage)
Concrete (wet) + Self-weight < L/360 or 1” AISC Design Guide 3 Ch. 5 recommendations
Post-Composite
Dead+Live < L/240 IBC 2018 Table 1604.3
Live < L/360 IBC 2018 Table 1604.3
Comparison of Results between Tedds and AISC Example I.2 (LRFD)
Component Tedds Result AISC Example I.2 % Difference
Pre-Composite (Construction Stage)
Beam Size W24x76 W24x76 -
Flexural Demand (Mu) 621.1 k-ft 624 kip-ft 0.5%a
Flexural Capacity (φMn) 677.2 k-ft 677 kip-ftb 0.0%
Shear Demand (Vu) 62.57 kips N/A -
Shear Capacity (φVn) 315.5 kips N/A -
Dead Load Deflection w/ camberc 1” - ¾” (camber) = 0.25” 1” - ¾” (camber) = 0.25” 0.0%
Post-Composite
Total number of shear studsd 55 studs 55 studs
Flexural Demand (Mu) 1,215.1 k-ft 1,220 kip-ft 0.4%
Flexural Capacity (φMn) 1,267.3 kip-ft 1,280 kip-ft 1.0%
Compression Block Depth (a) 1.83” 1.83” 0.0%
Steel Anchor Shear Capacity (∑Qn) 559.96 kips 560 kips 0.0%
% Composite Action 50% 50% 0.0%
Shear Demand (Vu) 121.97 kips 122 kips 0.0%
Shear Capacity (φVn) 315.48 kips 315 kips 0.0%
Total Deflectione 0.66” = L/545 < L/240 N/A -
Live Load Deflection (based on full design live load)e 0.60” = L/600 < L/360 0.543” = L/663 < L/360 10.5%f
Final Beam Design W24x76 (55) c=¾” W24x76 (55) c=¾” -
Comparison of Results between Tedds and AISC Example I.2 (ASD)
Component Tedds Result AISC Example I.2 % Difference
Pre-Composite (Construction Stage)
Beam Sizee W24x76 W24x76
Flexural Demand (Ma) 480.1 k-ft 482 kip-ft 0.4%a
Flexural Capacity (Mn/Ω)e 450.6 k-ft 450 kip-ftb 0.1%
Shear Demand (Va) 48.4 kips N/A -
Shear Capacity (Vn/Ω) 210.3 kips N/A -
Dead Load Deflection w/ camberc 1” - ¾” (camber) = 0.25” 1” - ¾” (camber) = 0.25” 0.0%
Post-Composite
Total number of shear studsd 55 studs 55 studs
Flexural Demand (Ma) 862.6 k-ft 863 kip-ft 0.0%
Flexural Capacity (M/Ω) 843.2 kip-ft 850 kip-ft 0.8%
Compression Block Depth (a) 1.83” 1.83” 0.0%
Steel Anchor Shear Capacity (∑Qn) 559.96 kips 560 kips 0.0%
% Composite Action 50% 50% 0.0%
Shear Demand (Va) 86.6 kips 86.6 kips 0.0%
Shear Capacity (Vn/Ω) 210.3 kips 210 kips 0.1%
Total Deflection 0.66” = L/545 < L/240 N/A -
Live Load Deflection (based on full design live load) 0.60” = L/600 < L/360 0.543” = L/663 < L/360 10.5%f
Final Beam Designe W24x76 (55) c=¾” W24x76 (55) c=¾” -

Comparison Notes

a The design example used a trial girder weight of 80 lb/ft, while Tedds used the final beam size weight of 76 lb/ft, leading to the small difference.

b AISC Table 3-2

c Tedds calculates the total construction stage deflection which includes all preconstruction dead loads and construction live loads. The value shown is with the construction live load removed.

d See Figures 2 and 3 for girder stud layout.

e When the composite girder is designed using the ASD method, a W24x76 beam is not suitable for pre- or post-composite loading. However, the AISC design example continues the design using a W24x76 girder. To follow suit, the Tedds calculations provide results for a W24x76 composite girder.

f The reason for the live load deflection discrepancy is that Tedds uses 27.5 studs (exactly half of the studs on the girder) to determine ⅀Qn, while the Design Example uses 27 studs (the number of studs on each side of the center stud on the girder). This difference affects the effective moment of inertia, which in turn affects the deflection. Also, it was assumed that the long-term concrete modulus is 33% of the short-term modulus, which further affects the deflection.

Conclusion

Upon reviewing the results above, it is evident that the solutions determined by Tedds match the AISC Design Example I.2 (apart from minor differences due to rounding and precision).

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