Composite Beam Secondary Member (LRFD & ASD) Verification Example

Tekla Structural Designer
Modified: 7 Feb 2025
2025
Tekla Structural Designer

Composite Beam Secondary Member (LRFD & ASD) Verification Example

Description

This verification example represents the analysis and design of a composite steel beam (secondary member) utilizing Tekla Structural Designer (TSD). This example is based on Design Example I.1 of the Companion to the AISC Steel Construction Manual Volume 1: Design Examples Version 15.1 (Pages I-4 through I-14). Comparisons and contrasts are tabularized and discussed regarding the results from TSD and the AISC Design Example. The TSD model used in this example is also provided via the link below.

Problem statement

Select an appropriate ASTM A992 W-shaped beam and determine the required number of ¾” ⌀ steel headed stud anchors. The beam will not be shored during construction.

References

International Building Code (IBC) 2018

AISC Steel Construction Manual 15th ed.

Companion to the AISC Steel Construction Manual Volume 1: Design Examples Version 15.1

ANSI/AISC 360-16: Specification for Structural Steel Buildings

ACI 318-14: Building Code Requirements for Structural Concrete and Commentary

Tekla Structural Designer models

The comparisons given below were made using ASD and LRFD example models (dated 22.11.2024) which were created in Tekla Structural Designer 2024 Service Pack 2. A zip file containing the example models can be downloaded from this page.

Note that the downloaded models can only be opened in the same, or a later version of the application.

Example information

4-½” normal weight concrete on 3” x 18 ga. (Vulcraft 3VLI-36) composite deck (total slab thickness = 7-½”)

γconcrete = 145 lb/ft3

f’c = 4 ksi

ASTM A992

Fy = 50 ksi

Fu = 65 ksi

¾” ⌀ Steel stud anchors

Fu = 65 ksi

Stud height = 3” + 1-½” = 4-½” (AISC Section I3.2c)

Short-term to long-term concrete elastic modulus = 3:1 (assumed)

Figure 1: Composite beam floor layout with secondary member analyzed in TSD
Applied Loads
Pre-Composite (Construction Stage)

Dead Load

75 lb/ft2 Composite slab and deck
5 lb/ft Self-weight of steel members. Automatic self-weight of steel determined by TSD was not used, and a self-weight load case of 5 lb/ft2 was used instead.
Construction Live Load 25 lb/ft2 Light duty (ASCE 37-14 Table 4-4)
Post-Composite
Dead 10 lb/ft2 Miscellaneous (HVAC, ceiling, floor covering, sprinklers, etc.)
Live 100 lb/ft2 Assembly occupancy (non-reducible). Live load is assumed to be 100% long-term as no information is provided in the Design Example. This value is found in the Load Case section for Live Load in TSD
Serviceability Criteria
Pre-Composite (Construction Stage)
Concrete (wet) + Self-weight < L/360 or 1” AISC Design Guide 3 Ch. 5 recommendations
Post-Composite
Dead+Live < L/240 IBC 2018 Table 1604.3
Live < L/360 IBC 2018 Table 1604.3
50% Live < 1” AISC Design Guide 3 Ch. 5 recommendations
Comparison of Results between Tekla Structural Designer and AISC Example I.1 (LRFD)
Component TSD Result AISC Example I.1 % Difference a
Pre-Composite (Construction Stage)
Flexural Demand (Mu) 344 k-ft 344 k-ft 0.0%
Flexural Capacity (φMn) 413 k-ft 413 kip-ft b 0.0%
Shear Demand (Vu) 30.6 kips 30.6 kips 0.0%
Shear Capacity (φVn) 237 kips 237 kips 0.0%
Dead Load Deflection w/ camberc 2.614” - 2” (camber) = 0.614” 2.59” - 2” (camber) = 0.59” 4.0% (less than 1/32”)
Post-Composite
Total number of shear studs 46 studs d 46 studs
Flexural Demand (Mu) 678 k-ft 678 kip-ft 0.0%
Flexural Capacity (φMn) 773 kip-ft 769 kip-ft 0.5%
Compression Block Depth (a) 0.959” 0.946” e 1.4%
Steel Anchor Shear Capacity (∑Qn) 391 kips 390 kips 0.3%
% Composite Action 53.2% 53.1% 0.2%
Shear Demand (Vu) 60.3 kips 60.3 kips 0.0%
Shear Capacity (φVn) 237 kips 237 kips 0.0%
Total Deflection 1.90” = L/284 < L/240 N/A N/A
Live Load Deflection (based on full design live load) 1.26” = L/429 < L/360 1.26” = L/429 < L/360 0.0%
Live Load Deflection (based on 50% design live load) 0.63” < 1” 0.63” < 1” 0.0%
Comparison of Results between Tekla Structural Designer and AISC Example I.1 (ASD)
Component TSD Result AISC Example I.1 % Difference a
Pre-Composite (Construction Stage)
Flexural Demand (Ma) 266 k-ft 266 kip-ft 0.0%
Flexural Capacity (Mn/Ω) 274 k-ft 274 kip-ft b 0.0%
Shear Demand (Va) 23.6 kips 23.6 kips 0.0%
Shear Capacity (Vn/Ω) 158 kips 158 kips b 0.0%
Dead Load Deflection w/ camberc 2.614” - 2” (camber) = 0.614” 2.59” - 2” (camber) = 0.59” 4.0% (less than 1/32”)
Post-Composite
Total number of shear studs 46 studsd 46 studs
Flexural Demand (Ma) 481 k-ft 481 kip-ft 0.0%
Flexural Capacity (M/Ω) 514 kip-ft 512 kip-ft 0.4%
Compression Block Depth (a) 0.959” 0.946” e 1.4%
Steel Anchor Shear Capacity (∑Qn) 391 kips 390 kips 0.30%
% Composite Action 53.2% 53.1% 0.2%
Shear Demand (Va) 42.8 kips 42.8 kips 0.0%
Shear Capacity (Vn/Ω) 158 kips 158 kips 0.06%
Total Deflection 1.90” = L/284 < L/240 N/A
Live Load Deflection (based on full design live load) 1.26” = L/429 < L/360 1.26” = L/429 < L/360 0.0%
Live Load Deflection (based on 50% design live load) 0.63” < 1” 0.63” < 1” 0.0%

Comparison Notes

a - The manufacturer’s data of 75 lb/ft2 uses an approximation of the deck weight (2.5 lb/ft2). TSD uses exact weight based on deck properties (i.e. 3” x 18 ga deck has a weight of 2.8 lb/ft2). The weight of the deck in TSD was changed to 2.5 lb/ft2 to align with the AISC Design Example.

b - AISC Table 3-2

c - Camber is based off of 80% self-weight and pre-composite dead load with a minimum ¾” camber and a maximum 2” camber.

d - Tekla Structural Designer autodesigns a more economical solution with 45 required studs, however to align with the AISC Design Example, 46 studs were used.

e - The compression block depth in the AISC Design Example is determined from the required horizontal shear (386 kips) instead of the provided shear strength of 46 anchors (390 kips).

Conclusion

Upon reviewing the results above, it is evident that the solutions for composite beam analysis and design determined by Tekla Structural Designer match the AISC Design Example I.1 (apart from minor differences due to rounding and precision).

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